Barbers in Real Villages
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Suppose there may be a village where the barber shaves all the other men that do not shave themselves. So the barber shaves himself. No contradiction. It is ok for the barber to shave himself.
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Posted on
Suppose there may be a village where the barber shaves all the other men that do not shave themselves. So the barber shaves himself. No contradiction. It is ok for the barber to shave himself.
Posted on
In this post we state that if $f \colon \mathbb{N} \to \mathbb{N}$ is a total function, and $A \subseteq \mathbb{N}$ is a finite set, then $\exists g: \mathbb{N} \to \mathbb{N}$ a primitive recursive function such that: $$f|_A = g|_A. \quad \square$$
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In this post we prove that
$$\neg \exists R \forall x \; x \in R \Leftrightarrow x \notin x.$$Indeed,
$$\forall R \exists x \; x \in R \Leftrightarrow x \in x,$$because
$$\forall R \; R \in R \Leftrightarrow R \in R. \quad \square$$Posted on
In this post we write natural numbers in decimal.
Let $n$ be a 100-digit natural number.
Let us form 20 of 5-digit numbers with the digits of $n$ in the order in that they appear in the decimal representation of $n$ (left to right).
Then $n$ is a multiple of 41 if and only if the sum of the 20 numbers mentioned above is a multiple of 41. (This works because $10^5 \equiv 1 \pmod{41}$.)